There are 10 dolls, including 4 green, 3 blue, and 3 red, in a container. Two dolls are picked out one by one at random. What is the probability that a green doll and then a blue doll will be selected?
A) 1/5
B) 1/3
C) 2/15
D) 1/15
E) 4/15
Solution (Posted in Jan 11th):
Answer is C, 4/10 * 3/9 = 2/5 * 1/3 = 2/15
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