Is the number ABC (where A, B, C are digits) divisible by p?
a. p = 7 and 2A + 10B + C is divisible by 7.
b. p = 3 and A + B + C is a multiple of 3.
Solution (Posted on Mar 9th):
Answer is D. Number is 100A + 10B + C = 98A + (2A + 10B + C). 98A is divisible by 7 and 2A + 10B + C is also divisible by 7 => Number is divisible by 7.
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